What is the integral of sin(t)cos^2(t) ?

The integral of sin(t)cos^2(t) is -(cos^3(t))/3+C

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integral of sin(t)cos^2(t)

\int sin (t) cos^{2} (t) d t

- \frac{cos ^{3} ( t )}{3} + C

Solution steps

\int sin (t) cos^{2} (t) d t

Apply u-substitution

: \int - u^{2} d u

= \int - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= - \frac{u ^{3}}{3}

Substitute back

u = cos (t)

= - \frac{cos ^{3} ( t )}{3}

Add a constant to the solution

= - \frac{cos ^{3} ( t )}{3} + C

x \to 0 lim (x^{3} + 2 x^{2} - 4 x + 4)

f (x) = 7 e^{0.03 x}, at x = 9

3 sin (x), 8 cos (x)

x \to 2 lim ((1 + x)^{\frac{1}{x}})

\int \frac{( 1 - x ^{2} )}{x ^{2}} d x

What is the integral of sin(t)cos^2(t) ?
The integral of sin(t)cos^2(t) is -(cos^3(t))/3+C