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Popular Calculus >

(2xy^2+2y)+(2x^2y+2x)y^'=0

Solution

(2 x y^{2} + 2 y) + (2 x^{2} y + 2 x) y^{^{'}} = 0

Solution

y = \frac{c _{1}}{x}

Solution steps

(2 x y^{2} + 2 y) + (2 x^{2} y + 2 x) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (2xy^2+2y)+(2x^2y+2x)y^'=0 ?
The solution for (2xy^2+2y)+(2x^2y+2x)y^'=0 is y=(c_{1})/x