What is the derivative of 2cos(-x) ?

The derivative of 2cos(-x) is -2sin(x)

What is the first derivative of 2cos(-x) ?

The first derivative of 2cos(-x) is -2sin(x)

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\frac{d}{d x} (2 cos (- x))

- 2 sin (x)

Solution steps

\frac{d}{d x} (2 cos (- x))

Simplify

2 cos (- x) : 2 cos (x)

= \frac{d}{d x} (2 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (x))

Apply the common derivative:

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 (- sin (x))

Simplify

= - 2 sin (x)

\frac{( x )}{( x + 2 ) ( x - 3 )}

\int \frac{x ^{2} + x + 1}{( x ^{2} + 1 ) ^{2}} d x

x \frac{d y}{d x} = y^{2} - y

\int_{1}^{4} t^{- \frac{3}{2}} d t

x^{^{''}} + 10 x^{^{'}} + 25 = 14 e^{- 5 t}

What is the derivative of 2cos(-x) ?
The derivative of 2cos(-x) is -2sin(x)
What is the first derivative of 2cos(-x) ?
The first derivative of 2cos(-x) is -2sin(x)