What is the integral from 1 to 4 of t^{-3/2} ?

The integral from 1 to 4 of t^{-3/2} is 1

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integral from 1 to 4 of t^{-3/2}

\int_{1}^{4} t^{- \frac{3}{2}} d t

1

Solution steps

\int_{1}^{4} t^{- \frac{3}{2}} d t

Apply the Power Rule

: [- \frac{2}{t ^{\frac{1}{2}}}]_{1}^{4}

= [- \frac{2}{t ^{\frac{1}{2}}}]_{1}^{4}

Compute the boundaries:

1

= 1

x^{^{''}} + 10 x^{^{'}} + 25 = 14 e^{- 5 t}

\frac{d y}{d t} = - 4 (y - 3)

x^{4} - 50 x^{2}

\frac{x ^{2}}{x + 1}

x \to 2 lim (9 - x)

What is the integral from 1 to 4 of t^{-3/2} ?
The integral from 1 to 4 of t^{-3/2} is 1