What is laplacetransform f(t)=e^{t+7} ?

The answer to laplacetransform f(t)=e^{t+7} is (e^7)/(s-1)

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laplacetransform f(t)=e^{t+7}

laplace transform

f (t) = e^{t + 7}

\frac{e ^{7}}{s - 1}

Solution steps

L {e^{t + 7}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{7} L {e^{t}}

L {e^{t}} : \frac{1}{s - 1}

= e^{7} \frac{1}{s - 1}

Refine

e^{7} \frac{1}{s - 1} : \frac{e ^{7}}{s - 1}

= \frac{e ^{7}}{s - 1}

3 y

\frac{d}{d x} (\frac{1}{3 x ^{2}} - \frac{5}{2 x} + 8 x - 6)

\frac{d}{d x} (2 cos (- x))

\frac{( x )}{( x + 2 ) ( x - 3 )}

\int \frac{x ^{2} + x + 1}{( x ^{2} + 1 ) ^{2}} d x

What is laplacetransform f(t)=e^{t+7} ?
The answer to laplacetransform f(t)=e^{t+7} is (e^7)/(s-1)