What is the derivative of arcsec(x-7x) ?

The derivative of arcsec(x-7x) is 1/(xsqrt(x^2-1))-7

What is the first derivative of arcsec(x-7x) ?

The first derivative of arcsec(x-7x) is 1/(xsqrt(x^2-1))-7

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\frac{d}{d x} (arcsec (x) - 7 x)

\frac{1}{x x ^{2} - 1} - 7

Solution steps

\frac{d}{d x} (arcsec (x) - 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arcsec (x)) - \frac{d}{d x} (7 x)

\frac{d}{d x} (arcsec (x)) = \frac{1}{x x ^{2} - 1}

\frac{d}{d x} (7 x) = 7

= \frac{1}{x x ^{2} - 1} - 7

\int \frac{1}{2 y - y ^{2}} d y

y = 2 x^{3} - 5 x + 1, (- 1, 4)

\int \frac{3 x}{x - 1} d x

h \to 0 lim (2)

\frac{d P}{d t} = \frac{1}{10} P (500 - P)

What is the derivative of arcsec(x-7x) ?
The derivative of arcsec(x-7x) is 1/(xsqrt(x^2-1))-7
What is the first derivative of arcsec(x-7x) ?
The first derivative of arcsec(x-7x) is 1/(xsqrt(x^2-1))-7