What is the tangent of y=2x^3-5x+1,(-1,4) ?

The tangent of y=2x^3-5x+1,(-1,4) is y=x+5

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tangent of y=2x^3-5x+1,(-1,4)

tangent of

y = 2 x^{3} - 5 x + 1, (- 1, 4)

y = x + 5

Solution steps

Find the slope of

y = 2 x^{3} - 5 x + 1 : \frac{d y}{d x} = 6 x^{2} - 5

Compute the slope of

y = 2 x^{3} - 5 x + 1

(- 1, 4) : m = 1

Find the line with slope m=

1

and passing through

(- 1, 4) : y = x + 5

y = x + 5

\int \frac{3 x}{x - 1} d x

h \to 0 lim (2)

\frac{d P}{d t} = \frac{1}{10} P (500 - P)

\int sec^{2} (5 x) tan^{4} (5 x) d x

x \to 1 lim (\frac{x ^{2} - 4}{x - 1})

What is the tangent of y=2x^3-5x+1,(-1,4) ?
The tangent of y=2x^3-5x+1,(-1,4) is y=x+5