What is the derivative of-8ln(x) ?

The derivative of-8ln(x) is -8/x

What is the first derivative of-8ln(x) ?

The first derivative of-8ln(x) is -8/x

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\frac{d}{d x} (- 8 ln (x))

- \frac{8}{x}

Solution steps

\frac{d}{d x} (- 8 ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - 8 \cdot \frac{1}{x}

Simplify

- 8 \cdot \frac{1}{x} : - \frac{8}{x}

= - \frac{8}{x}

y = 7 x^{- 7}

(3 x + 2 y + 2 y^{2}) d x + (x + 2 x y) d y = 0

\frac{d}{d t} (k^{2} sin^{2} (t))

2 csc^{3} (x) + 3 c t a (x^{2})

x \to 0 - lim (6 + \frac{1}{x})