en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dt)(k^2sin^2(t))

Solution

\frac{d}{d t} (k^{2} sin^{2} (t))

Solution

k^{2} sin (2 t)

Solution steps

\frac{d}{d t} (k^{2} sin^{2} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= k^{2} \frac{d}{d t} (sin^{2} (t))

Apply the chain rule:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= k^{2} \cdot 2 sin (t) cos (t)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= k^{2} sin (2 t)

Popular Examples

derivative of 2csc^3(sqrt(x))+3cta(x^2)derivative of

2 csc^{3} (x) + 3 c t a (x^{2})

limit as x approaches 0-of 6+1/x

x \to 0 - lim (6 + \frac{1}{x})

(\partial)/(\partial x)(ye^{-xy})

\frac{\partial}{\partial x} (y e^{- x y})

(\partial)/(\partial x)(x/(x+1))

\frac{\partial}{\partial x} (\frac{x}{x + 1})

limit as x approaches infinity of x(1)^x

x \to \infty lim (x (1)^{x})

Frequently Asked Questions (FAQ)

What is the d/(dt)(k^2sin^2(t)) ?
The d/(dt)(k^2sin^2(t)) is k^2sin(2t)
What is the first d/(dt)(k^2sin^2(t)) ?
The first d/(dt)(k^2sin^2(t)) is k^2sin(2t)