What is the integral from 1 to infinity of x/(4+x^2) ?

The integral from 1 to infinity of x/(4+x^2) is diverges

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integral from 1 to infinity of x/(4+x^2)

\int_{1}^{\infty} \frac{x}{4 + x ^{2}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{4 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{4 + x ^{2}} d x = \frac{1}{2} ln 4 + x^{2} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{4 + x ^{2}} d x =

diverges

= diverges

\frac{\partial}{\partial x} (ln (y - 2 x))

(x + y)^{2} d x + (2 x y + x^{2} - 1) d y = 0

f (x) = 2^{50}

\int x (1 - x)^{7} d x

f (x) = 3 x^{3} + 3 x^{2} - 11 x - 1

What is the integral from 1 to infinity of x/(4+x^2) ?
The integral from 1 to infinity of x/(4+x^2) is diverges