What is (\partial)/(\partial x)(ln(y-2x)) ?

The answer to (\partial)/(\partial x)(ln(y-2x)) is -2/(y-2x)

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(\partial)/(\partial x)(ln(y-2x))

\frac{\partial}{\partial x} (ln (y - 2 x))

- \frac{2}{y - 2 x}

Solution steps

\frac{\partial}{\partial x} (ln (y - 2 x))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{y - 2 x} \frac{\partial}{\partial x} (y - 2 x)

= \frac{1}{y - 2 x} \frac{\partial}{\partial x} (y - 2 x)

\frac{\partial}{\partial x} (y - 2 x) = - 2

= \frac{1}{y - 2 x} (- 2)

Simplify

\frac{1}{y - 2 x} (- 2) : - \frac{2}{y - 2 x}

= - \frac{2}{y - 2 x}

(x + y)^{2} d x + (2 x y + x^{2} - 1) d y = 0

f (x) = 2^{50}

\int x (1 - x)^{7} d x

f (x) = 3 x^{3} + 3 x^{2} - 11 x - 1

y^{^{''}} + 9 y = 3 csc^{2} (3 t)

What is (\partial)/(\partial x)(ln(y-2x)) ?
The answer to (\partial)/(\partial x)(ln(y-2x)) is -2/(y-2x)