What is the derivative of 2(2x^5-3x+2)^8 ?

The derivative of 2(2x^5-3x+2)^8 is 16(2x^5-3x+2)^7(10x^4-3)

What is the first derivative of 2(2x^5-3x+2)^8 ?

The first derivative of 2(2x^5-3x+2)^8 is 16(2x^5-3x+2)^7(10x^4-3)

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derivative of

2 (2 x^{5} - 3 x + 2)^{8}

16 (2 x^{5} - 3 x + 2)^{7} (10 x^{4} - 3)

Solution steps

\frac{d}{d x} (2 (2 x^{5} - 3 x + 2)^{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((2 x^{5} - 3 x + 2)^{8})

Apply the chain rule:

8 (2 x^{5} - 3 x + 2)^{7} \frac{d}{d x} (2 x^{5} - 3 x + 2)

= 8 (2 x^{5} - 3 x + 2)^{7} \frac{d}{d x} (2 x^{5} - 3 x + 2)

\frac{d}{d x} (2 x^{5} - 3 x + 2) = 10 x^{4} - 3

= 2 \cdot 8 (2 x^{5} - 3 x + 2)^{7} (10 x^{4} - 3)

Simplify

= 16 (2 x^{5} - 3 x + 2)^{7} (10 x^{4} - 3)

\int 3 x y

\int \frac{1}{( 2 - x ) 1 - x} d x

\int (t + 7) e^{2 t + 3} d t

\frac{d}{d x} (5 x + 6 x)

y^{2} - 7 x = 1, x - y = 1

What is the derivative of 2(2x^5-3x+2)^8 ?
The derivative of 2(2x^5-3x+2)^8 is 16(2x^5-3x+2)^7(10x^4-3)
What is the first derivative of 2(2x^5-3x+2)^8 ?
The first derivative of 2(2x^5-3x+2)^8 is 16(2x^5-3x+2)^7(10x^4-3)