What is the derivative of (126-0.5x)x-50x-31.75 ?

The derivative of (126-0.5x)x-50x-31.75 is -x+76

What is the first derivative of (126-0.5x)x-50x-31.75 ?

The first derivative of (126-0.5x)x-50x-31.75 is -x+76

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derivative of

(126 - 0.5 x) x - 50 x - 31.75

- x + 76

Solution steps

\frac{d}{d x} ((126 - 0.5 x) x - 50 x - 31.75)

Simplify

(126 - 0.5 x) x - 50 x - 31.75 : - 0.5 x^{2} + 76 x - 31.75

= \frac{d}{d x} (- 0.5 x^{2} + 76 x - 31.75)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.5 x^{2}) + \frac{d}{d x} (76 x) - \frac{d}{d x} (31.75)

\frac{d}{d x} (0.5 x^{2}) = x

\frac{d}{d x} (76 x) = 76

\frac{d}{d x} (31.75) = 0

= - x + 76 - 0

Simplify

= - x + 76

1 - \frac{d v}{d x} = cos (v)

\frac{d ^{2}}{d x ^{2}} (x^{2} + 9)

f (x) = - x^{2} - x + 3, at x = - 3

\int x^{2} 8 - x^{2} d x

\int cot^{2} (x) (1 + tan^{2} (x)) d x

What is the derivative of (126-0.5x)x-50x-31.75 ?
The derivative of (126-0.5x)x-50x-31.75 is -x+76
What is the first derivative of (126-0.5x)x-50x-31.75 ?
The first derivative of (126-0.5x)x-50x-31.75 is -x+76