What is the solution for y^'= y/x+x/y ?

The solution for y^'= y/x+x/y is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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y^'= y/x+x/y

y^{^{'}} = \frac{y}{x} + \frac{x}{y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{y}{x} + \frac{x}{y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y^{^{''}} + y^{^{'}} = sin (20 x)

\frac{d y}{d x} = \frac{1}{10} y cos^{2} (y)

\frac{d}{d x} (\frac{x ^{2} + 32 x}{8})

\int_{0}^{1} 2 π (2 - y) (2 y^{2}) d y

\int_{2}^{3} \frac{1}{x ^{2}} d x

What is the solution for y^'= y/x+x/y ?
The solution for y^'= y/x+x/y is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}