What is the integral from 2 to 3 of 1/(x^2) ?

The integral from 2 to 3 of 1/(x^2) is 1/6

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integral from 2 to 3 of 1/(x^2)

\int_{2}^{3} \frac{1}{x ^{2}} d x

\frac{1}{6}

Solution steps

\int_{2}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{3}

= [- \frac{1}{x}]_{2}^{3}

Compute the boundaries:

\frac{1}{6}

= \frac{1}{6}

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\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{\frac{3}{2}})

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What is the integral from 2 to 3 of 1/(x^2) ?
The integral from 2 to 3 of 1/(x^2) is 1/6