What is the integral of cos(6y)-cos(-6y) ?

The integral of cos(6y)-cos(-6y) is C

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integral of cos(6y)-cos(-6y)

\int cos (6 y) - cos (- 6 y) d y

C

Solution steps

\int cos (6 y) - cos (- 6 y) d y

cos (6 y) - cos (- 6 y) = 0

= \int 0 d y

Integral of a constant:

\int a d x = a x

= 0 \cdot y

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

\frac{d}{d x} (\frac{1}{3 x + 6})

(\frac{1}{1 - 2 x})^{3}

\int \frac{x ^{3} - 1}{x ^{3} + x} d x

\int \frac{1}{x - 1 \cdot ( x ^{2} )} d x

\frac{d}{d x} (- x (2 x - y^{3}))

What is the integral of cos(6y)-cos(-6y) ?
The integral of cos(6y)-cos(-6y) is C