What is (\partial)/(\partial x)(3x^2-4xy) ?

The answer to (\partial)/(\partial x)(3x^2-4xy) is 6x-4y

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(\partial)/(\partial x)(3x^2-4xy)

\frac{\partial}{\partial x} (3 x^{2} - 4 x y)

6 x - 4 y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 4 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (4 x y) = 4 y

= 6 x - 4 y

What is (\partial)/(\partial x)(3x^2-4xy) ?
The answer to (\partial)/(\partial x)(3x^2-4xy) is 6x-4y