What is the tangent of f(x)=(x^2+2)^2,(0,4) ?

The tangent of f(x)=(x^2+2)^2,(0,4) is y=4

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tangent of f(x)=(x^2+2)^2,(0,4)

tangent of

f (x) = (x^{2} + 2)^{2}, (0, 4)

y = 4

Solution steps

Find the slope of

f (x) = (x^{2} + 2)^{2} : \frac{df ( x )}{d x} = 4 x (x^{2} + 2)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(0, 4) : y = 4

y = 4

What is the tangent of f(x)=(x^2+2)^2,(0,4) ?
The tangent of f(x)=(x^2+2)^2,(0,4) is y=4