inverselaplace (0.6)/(s+10)

פתרון

inverse laplace

\frac{0.6}{s + 10}

0.6 e^{- 10 t}

צעדי פתרון

L^{- 1} {\frac{0.6}{s + 10}}

= L^{- 1} {0.6 \cdot \frac{1}{s + 10}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 0.6 L^{- 1} {\frac{1}{s + 10}}

L^{- 1} {\frac{1}{s - a}} = e^{a t}

:Use Inverse Laplace Transform table

L^{- 1} {\frac{1}{s + 10}} = e^{- 10 t}

= 0.6 e^{- 10 t}