What is the derivative of \sqrt[4]{x} ?

The derivative of \sqrt[4]{x} is 1/(4x^{3/4)}

What is the first derivative of \sqrt[4]{x} ?

The first derivative of \sqrt[4]{x} is 1/(4x^{3/4)}

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derivative of

\frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

\frac{1}{4} x^{\frac{1}{4} - 1} : \frac{1}{4 x ^{\frac{3}{4}}}

= \frac{1}{4 x ^{\frac{3}{4}}}

\frac{d}{d y} (e^{x e^{y}})

x, x - 2, y = 0

x \to 0 lim (\frac{sin ( k x )}{x})

\int \frac{3 r}{1 - r ^{2}} d r

\int cos^{2} (4 x) d x

What is the derivative of \sqrt[4]{x} ?
The derivative of \sqrt[4]{x} is 1/(4x^{3/4)}
What is the first derivative of \sqrt[4]{x} ?
The first derivative of \sqrt[4]{x} is 1/(4x^{3/4)}