What is (\partial)/(\partial x)(sin(3x+yz)) ?

The answer to (\partial)/(\partial x)(sin(3x+yz)) is cos(3x+yz)*3

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(\partial)/(\partial x)(sin(3x+yz))

\frac{\partial}{\partial x} (sin (3 x + yz))

cos (3 x + yz) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x + yz))

Treat

y, z

as constants

Apply the chain rule:

cos (3 x + yz) \frac{\partial}{\partial x} (3 x + yz)

= cos (3 x + yz) \frac{\partial}{\partial x} (3 x + yz)

\frac{\partial}{\partial x} (3 x + yz) = 3

= cos (3 x + yz) \cdot 3

\int_{3}^{\infty} \frac{8}{x ^{2} - x} d x

F (s) = \frac{6}{s ^{2} + 4}

\int - 6 sin (2 x) + 3 cos (3 x) d x

\frac{d y}{d x} = \frac{15 x}{y}

What is (\partial)/(\partial x)(sin(3x+yz)) ?
The answer to (\partial)/(\partial x)(sin(3x+yz)) is cos(3x+yz)*3