What is the solution for (dy)/(dt)=20-y/(230+t) ?

The solution for (dy)/(dt)=20-y/(230+t) is y=(10(t^2+460t))/(230+t)+(c_{1})/(230+t)

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(dy)/(dt)=20-y/(230+t)

\frac{d y}{d t} = 20 - \frac{y}{230 + t}

y = \frac{10 ( t ^{2} + 460 t )}{230 + t} + \frac{c _{1}}{230 + t}

Solution steps

\frac{d y}{d t} = 20 - \frac{y}{230 + t}

Solve linear ODE:

y = \frac{10 ( t ^{2} + 460 t )}{230 + t} + \frac{c _{1}}{230 + t}

y = \frac{10 ( t ^{2} + 460 t )}{230 + t} + \frac{c _{1}}{230 + t}

\frac{1}{( x + 3 ) ^{2}}

\int tanh (x) d x

\frac{\partial}{\partial z} (x y z^{2})

\frac{d}{d x} (sin (3 x) + cos (3 x))

\int 7 arccos (x) d x

What is the solution for (dy)/(dt)=20-y/(230+t) ?
The solution for (dy)/(dt)=20-y/(230+t) is y=(10(t^2+460t))/(230+t)+(c_{1})/(230+t)