What is (\partial)/(\partial z)(xyz^2) ?

The answer to (\partial)/(\partial z)(xyz^2) is 2xyz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(xyz^2)

\frac{\partial}{\partial z} (x y z^{2})

2 x yz

Solution steps

\frac{\partial}{\partial z} (x y z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x y \cdot 2 z^{2 - 1}

Simplify

= 2 x yz

\frac{d}{d x} (sin (3 x) + cos (3 x))

\int 7 arccos (x) d x

\int \frac{1}{x ^{2} + b ^{2}} d x

\int e^{2 x} + x \cdot (e^{2 x} + \frac{1}{2}) d x

f (x) = x^{x} (ln (x) + 1)

What is (\partial)/(\partial z)(xyz^2) ?
The answer to (\partial)/(\partial z)(xyz^2) is 2xyz