What is (\partial)/(\partial x)(ycos(x-y)-z) ?

The answer to (\partial)/(\partial x)(ycos(x-y)-z) is -ysin(x-y)

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(\partial)/(\partial x)(ycos(x-y)-z)

\frac{\partial}{\partial x} (y cos (x - y) - z)

- y sin (x - y)

Solution steps

\frac{\partial}{\partial x} (y cos (x - y) - z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y cos (x - y)) - \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (y cos (x - y)) = - y sin (x - y)

\frac{\partial}{\partial x} (z) = 0

= - y sin (x - y) - 0

Simplify

= - y sin (x - y)

\int (x^{4} (5 - x^{2})) d x

x \to 1000 lim (18 π^{2})

\frac{\partial}{\partial x} (x (2 x - y^{3}))

y = 5 x + 6, (2, 4)

\int (x + 3)^{2} sin (x) d x

What is (\partial)/(\partial x)(ycos(x-y)-z) ?
The answer to (\partial)/(\partial x)(ycos(x-y)-z) is -ysin(x-y)