What is the slope ofintercept (-5,5),(5,-5) ?

The slope ofintercept (-5,5),(5,-5) is y=-x+0

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slope ofintercept (-5,5),(5,-5)

slope intercept

(- 5, 5), (5, - 5)

y = - x + 0

Solution steps

Compute the slope

(- 5, 5), (5, - 5) : m = - 1

Compute the

y

intercept:

b = 0

Construct the line equation

y = mx + b

where

m = - 1

and

b = 0

y = - x + 0

(ln (3))^{^{'}}

\frac{\partial}{\partial x} (z + 1 - x e^{y} cos (z))

y = (arctan (3 x))^{2}

y^{^{''}} + 9 y^{^{'}} = 5 csc^{2} (3 t)

\frac{\partial}{\partial x} (y cos (x - y) - z)

What is the slope ofintercept (-5,5),(5,-5) ?
The slope ofintercept (-5,5),(5,-5) is y=-x+0