What is the derivative of-8/(sqrt(x)) ?

The derivative of-8/(sqrt(x)) is 4/(x^{3/2)}

What is the first derivative of-8/(sqrt(x)) ?

The first derivative of-8/(sqrt(x)) is 4/(x^{3/2)}

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derivative of

- \frac{8}{x}

\frac{4}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (- \frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 8 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

- 8 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : \frac{4}{x ^{\frac{3}{2}}}

= \frac{4}{x ^{\frac{3}{2}}}

3 x^{2}

\int \frac{1}{( x + 1 ) ^{\frac{3}{2}}} d x

\int π e^{2 x} d x

\int x ln ∣ x ∣ d x

x \to 8 lim (ln (9 - x))

What is the derivative of-8/(sqrt(x)) ?
The derivative of-8/(sqrt(x)) is 4/(x^{3/2)}
What is the first derivative of-8/(sqrt(x)) ?
The first derivative of-8/(sqrt(x)) is 4/(x^{3/2)}