What is the derivative of 2(x-2^2+1) ?

The derivative of 2(x-2^2+1) is 4x-8

What is the first derivative of 2(x-2^2+1) ?

The first derivative of 2(x-2^2+1) is 4x-8

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\frac{d}{d x} (2 (x - 2)^{2} + 1)

4 x - 8

Solution steps

\frac{d}{d x} (2 (x - 2)^{2} + 1)

Simplify

2 (x - 2)^{2} + 1 : 2 x^{2} - 8 x + 9

= \frac{d}{d x} (2 x^{2} - 8 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (9)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (9) = 0

= 4 x - 8 + 0

Simplify

= 4 x - 8

\int \frac{1}{2 x ^{3} - 3 x ^{2}} d x

x^{2} (3 - x)

c y^{- 6}

x \to 1 lim (x^{3} - 2 x^{2} + x - 3)

x^{6}

What is the derivative of 2(x-2^2+1) ?
The derivative of 2(x-2^2+1) is 4x-8
What is the first derivative of 2(x-2^2+1) ?
The first derivative of 2(x-2^2+1) is 4x-8