What is the integral of 1/(1-cos^2(x)) ?

The integral of 1/(1-cos^2(x)) is -cot(x)+C

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integral of 1/(1-cos^2(x))

\int \frac{1}{1 - cos ^{2} ( x )} d x

- cot (x) + C

Solution steps

\int \frac{1}{1 - cos ^{2} ( x )} d x

Rewrite using trig identities

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

y = 5 x - x^{2}, y = - x

\frac{\partial}{\partial x} (3 y cos (x))

\frac{1}{s [ 5 + s ]}

y^{^{''}} - 12 y^{^{'}} + 36 y = 0

What is the integral of 1/(1-cos^2(x)) ?
The integral of 1/(1-cos^2(x)) is -cot(x)+C