What is (\partial)/(\partial x)(3ycos(x)) ?

The answer to (\partial)/(\partial x)(3ycos(x)) is -3ysin(x)

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(\partial)/(\partial x)(3ycos(x))

\frac{\partial}{\partial x} (3 y cos (x))

- 3 y sin (x)

Solution steps

\frac{\partial}{\partial x} (3 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 3 y (- sin (x))

Simplify

= - 3 y sin (x)

\frac{1}{s [ 5 + s ]}

y^{^{''}} - 12 y^{^{'}} + 36 y = 0

\frac{d ^{2}}{d x ^{2}} (cos (x))

x \to 0 - lim (\frac{18}{tan ( x )})

\frac{( x - 1 )}{x}

What is (\partial)/(\partial x)(3ycos(x)) ?
The answer to (\partial)/(\partial x)(3ycos(x)) is -3ysin(x)