What is the derivative of (e^x+1/(x^2)) ?

The derivative of (e^x+1/(x^2)) is (e^xx-2(e^x+1))/(x^3)

What is the first derivative of (e^x+1/(x^2)) ?

The first derivative of (e^x+1/(x^2)) is (e^xx-2(e^x+1))/(x^3)

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\frac{d}{d x} (\frac{e ^{x} + 1}{x ^{2}})

\frac{e ^{x} x - 2 ( e ^{x} + 1 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{e ^{x} + 1}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} + 1 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( e ^{x} + 1 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (e^{x} + 1) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{e ^{x} x ^{2} - 2 x ( e ^{x} + 1 )}{( x ^{2} ) ^{2}}

Simplify

\frac{e ^{x} x ^{2} - 2 x ( e ^{x} + 1 )}{( x ^{2} ) ^{2}} : \frac{e ^{x} x - 2 ( e ^{x} + 1 )}{x ^{3}}

= \frac{e ^{x} x - 2 ( e ^{x} + 1 )}{x ^{3}}

\frac{d}{d x} (6 x^{4} - 2 x^{3} - 12 x^{2} + 3 x + 3)

\frac{d ^{2}}{d x ^{2}} (\frac{4}{5 t ^{6}})

e^{2 - x}

y^{^{'}} = 23 x y

\int (tan (2 x) - sec (2 x)) d x

What is the derivative of (e^x+1/(x^2)) ?
The derivative of (e^x+1/(x^2)) is (e^xx-2(e^x+1))/(x^3)
What is the first derivative of (e^x+1/(x^2)) ?
The first derivative of (e^x+1/(x^2)) is (e^xx-2(e^x+1))/(x^3)