derivative of 6x^4-2x^3-12x^2+3x+3

Lösung

\frac{d}{d x} (6 x^{4} - 2 x^{3} - 12 x^{2} + 3 x + 3)

24 x^{3} - 6 x^{2} - 24 x + 3

Schritte zur Lösung

\frac{d}{d x} (6 x^{4} - 2 x^{3} - 12 x^{2} + 3 x + 3)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (12 x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (3)

\frac{d}{d x} (6 x^{4}) = 24 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (12 x^{2}) = 24 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (3) = 0

= 24 x^{3} - 6 x^{2} - 24 x + 3 + 0

Vereinfache

= 24 x^{3} - 6 x^{2} - 24 x + 3

\frac{d ^{2}}{d x ^{2}} (\frac{4}{5 t ^{6}})

d er i v a t i v e e^{2 - x}

y^{^{'}} = 23 x y

\int (tan (2 x) - sec (2 x)) d x

\int \frac{x}{x ^{2} + 4 x + 5} d x