What is the d/(dy)((3x)/(2y)) ?

The d/(dy)((3x)/(2y)) is -(3x)/(2y^2)

What is the first d/(dy)((3x)/(2y)) ?

The first d/(dy)((3x)/(2y)) is -(3x)/(2y^2)

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\frac{d}{d y} (\frac{3 x}{2 y})

- \frac{3 x}{2 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{3 x}{2 y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3 x}{2} \frac{d}{d y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{3 x}{2} \frac{d}{d y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3 x}{2} (- 1 \cdot y^{- 1 - 1})

Simplify

\frac{3 x}{2} (- 1 \cdot y^{- 1 - 1}) : - \frac{3 x}{2 y ^{2}}

= - \frac{3 x}{2 y ^{2}}

\int \frac{1}{sin ^{2} ( x ) + tan ^{2} ( x )} d x

y = - x, y = 2 - x, y = 0

y = \frac{3 x ^{2}}{2 x + 4}

\int 2 x sin^{2} (x) d x

\frac{\partial}{\partial x} (2 A y (L - x))

What is the d/(dy)((3x)/(2y)) ?
The d/(dy)((3x)/(2y)) is -(3x)/(2y^2)
What is the first d/(dy)((3x)/(2y)) ?
The first d/(dy)((3x)/(2y)) is -(3x)/(2y^2)