What is (\partial)/(\partial x)(2Ay(L-x)) ?

The answer to (\partial)/(\partial x)(2Ay(L-x)) is -2Ay

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(\partial)/(\partial x)(2Ay(L-x))

\frac{\partial}{\partial x} (2 A y (L - x))

- 2 A y

Solution steps

\frac{\partial}{\partial x} (2 A y (L - x))

Treat

A, L, y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 A y \frac{\partial}{\partial x} (L - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 A y (\frac{\partial}{\partial x} (L) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (L) = 0

\frac{\partial}{\partial x} (x) = 1

= 2 A y (0 - 1)

Simplify

= - 2 A y

\int sec^{2} (7 - 4 x) d x

\int (9 x^{2} + 6 x) d x

\int_{0}^{3} \frac{1}{( x - 1 ) ^{2}} d x

y = 6 x - x^{2}, y = 2 x

What is (\partial)/(\partial x)(2Ay(L-x)) ?
The answer to (\partial)/(\partial x)(2Ay(L-x)) is -2Ay