y^'-2/x y=(y^5)/(x^2),y(1)=1

Lösung

y^{^{'}} - \frac{2}{x} y = \frac{y ^{5}}{x ^{2}}, y (1) = 1

y = \frac{4 7 x ^{2}}{4 - 4 x ^{7} + 11}

Schritte zur Lösung

y^{'} (x) - \frac{2}{x} y = \frac{y ^{5}}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{4 7 x ^{2}}{4 - 4 x ^{7} + 11}

y = \frac{4 7 x ^{2}}{4 - 4 x ^{7} + 11}

\frac{d}{d x} (2 x^{2} + x - 6)

\frac{d}{d x} (cot (6 - x))

\frac{d}{d x} (\frac{sin ( x ) sec ( x )}{1 + x tan ( x )})

x \to 3 lim (2 3 - x)

\frac{\partial}{\partial x} ((e^{x} + e^{y})^{7})