What is the derivative of 2x^2+x-6 ?

The derivative of 2x^2+x-6 is 4x+1

What is the first derivative of 2x^2+x-6 ?

The first derivative of 2x^2+x-6 is 4x+1

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\frac{d}{d x} (2 x^{2} + x - 6)

4 x + 1

Solution steps

\frac{d}{d x} (2 x^{2} + x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 4 x + 1 - 0

Simplify

= 4 x + 1

\frac{d}{d x} (cot (6 - x))

\frac{d}{d x} (\frac{sin ( x ) sec ( x )}{1 + x tan ( x )})

x \to 3 lim (2 3 - x)

\frac{\partial}{\partial x} ((e^{x} + e^{y})^{7})

\frac{\partial}{\partial x} (x ln (z^{3} + x^{3}))

What is the derivative of 2x^2+x-6 ?
The derivative of 2x^2+x-6 is 4x+1
What is the first derivative of 2x^2+x-6 ?
The first derivative of 2x^2+x-6 is 4x+1