derivative of 2x^2+x-6

解答

\frac{d}{d x} (2 x^{2} + x - 6)

4 x + 1

求解步骤

\frac{d}{d x} (2 x^{2} + x - 6)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 4 x + 1 - 0

化简

= 4 x + 1

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