What is the derivative of 2x^2-4x+3 ?

The derivative of 2x^2-4x+3 is 4x-4

What is the first derivative of 2x^2-4x+3 ?

The first derivative of 2x^2-4x+3 is 4x-4

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\frac{d}{d x} (2 x^{2} - 4 x + 3)

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

f (x) = 139 + \frac{36}{x} + \frac{x ^{2}}{16}

x^{^{''}} - 6 x^{^{'}} + 25 x = 64 e^{- t}

\frac{d}{d x} (- 7 x^{3})

\frac{\partial}{\partial y} (ln (x^{2} + 1) + y^{2})

arctan (0)

What is the derivative of 2x^2-4x+3 ?
The derivative of 2x^2-4x+3 is 4x-4
What is the first derivative of 2x^2-4x+3 ?
The first derivative of 2x^2-4x+3 is 4x-4