What is the derivative of f(x)=139+(36)/x+(x^2)/(16) ?

The derivative of f(x)=139+(36)/x+(x^2)/(16) is x/8-(36)/(x^2)

What is the first derivative of f(x)=139+(36)/x+(x^2)/(16) ?

The first derivative of f(x)=139+(36)/x+(x^2)/(16) is x/8-(36)/(x^2)

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derivative of

f (x) = 139 + \frac{36}{x} + \frac{x ^{2}}{16}

\frac{x}{8} - \frac{36}{x ^{2}}

Solution steps

\frac{d}{d x} (139 + \frac{36}{x} + \frac{x ^{2}}{16})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (139) + \frac{d}{d x} (\frac{36}{x}) + \frac{d}{d x} (\frac{x ^{2}}{16})

\frac{d}{d x} (139) = 0

\frac{d}{d x} (\frac{36}{x}) = - \frac{36}{x ^{2}}

\frac{d}{d x} (\frac{x ^{2}}{16}) = \frac{x}{8}

= 0 - \frac{36}{x ^{2}} + \frac{x}{8}

Simplify

= \frac{x}{8} - \frac{36}{x ^{2}}

x^{^{''}} - 6 x^{^{'}} + 25 x = 64 e^{- t}

\frac{d}{d x} (- 7 x^{3})

\frac{\partial}{\partial y} (ln (x^{2} + 1) + y^{2})

arctan (0)

x \to 1 lim (e^{x^{3} - x})

What is the derivative of f(x)=139+(36)/x+(x^2)/(16) ?
The derivative of f(x)=139+(36)/x+(x^2)/(16) is x/8-(36)/(x^2)
What is the first derivative of f(x)=139+(36)/x+(x^2)/(16) ?
The first derivative of f(x)=139+(36)/x+(x^2)/(16) is x/8-(36)/(x^2)