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Beliebt Rechnen >

y^'=(x(x^2+1))/(4y^3),y(0)=-1/(sqrt(2))

Lösung

y^{^{'}} = \frac{x ( x ^{2} + 1 )}{4 y ^{3}}, y (0) = - \frac{1}{2}

Lösung

Schritte zur Lösung

y^{'} (x) = \frac{x ( x ^{2} + 1 )}{4 y ^{3}}

Solve separable ODE:

Graph

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