What is the tangent of f(x)=2x^4+3x-3,(2,35) ?

The tangent of f(x)=2x^4+3x-3,(2,35) is y=67x-99

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tangent of f(x)=2x^4+3x-3,(2,35)

tangent of

f (x) = 2 x^{4} + 3 x - 3, (2, 35)

y = 67 x - 99

Solution steps

Find the slope of

f (x) = 2 x^{4} + 3 x - 3 : \frac{df ( x )}{d x} = 8 x^{3} + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 67

Find the line with slope m=

67

and passing through

(2, 35) : y = 67 x - 99

y = 67 x - 99

d er i v a t i v e 9 a^{2} + 8 a - 56

t = 0 \sum \infty \frac{1}{t ^{0.51}}

f (x) = (\frac{x}{4 2 x + 1})^{\frac{1}{x}}

\int - 3 x^{2} - 6 x + 45 d x

t an g e n t f (x) = \frac{1}{x ^{4}}, at x = 1

What is the tangent of f(x)=2x^4+3x-3,(2,35) ?
The tangent of f(x)=2x^4+3x-3,(2,35) is y=67x-99