What is the sum from t=0 to infinity of 1/(t^{0.51)} ?

The sum from t=0 to infinity of 1/(t^{0.51)} is diverges

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sum from t=0 to infinity of 1/(t^{0.51)}

t = 0 \sum \infty \frac{1}{t ^{0.51}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.51}}

Apply p-Series Test:

diverges

= diverges

f (x) = (\frac{x}{4 2 x + 1})^{\frac{1}{x}}

\int - 3 x^{2} - 6 x + 45 d x

t an g e n t f (x) = \frac{1}{x ^{4}}, at x = 1

\int_{6}^{8} \frac{32}{( x - 6 ) ^{3}} d x

y^{^{'}} + y = e^{x} y^{2}

What is the sum from t=0 to infinity of 1/(t^{0.51)} ?
The sum from t=0 to infinity of 1/(t^{0.51)} is diverges