What is the derivative of (x^4+7x^3+14x^2/(x+3)) ?

The derivative of (x^4+7x^3+14x^2/(x+3)) is (3x^4+26x^3+77x^2+84x)/((x+3)^2)

What is the first derivative of (x^4+7x^3+14x^2/(x+3)) ?

The first derivative of (x^4+7x^3+14x^2/(x+3)) is (3x^4+26x^3+77x^2+84x)/((x+3)^2)

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\frac{d}{d x} (\frac{x ^{4} + 7 x ^{3} + 14 x ^{2}}{x + 3})

\frac{3 x ^{4} + 26 x ^{3} + 77 x ^{2} + 84 x}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{4} + 7 x ^{3} + 14 x ^{2}}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{4} + 7 x ^{3} + 14 x ^{2} ) ( x + 3 ) - \frac{d}{d x} ( x + 3 ) ( x ^{4} + 7 x ^{3} + 14 x ^{2} )}{( x + 3 ) ^{2}}

\frac{d}{d x} (x^{4} + 7 x^{3} + 14 x^{2}) = 4 x^{3} + 21 x^{2} + 28 x

\frac{d}{d x} (x + 3) = 1

= \frac{( 4 x ^{3} + 21 x ^{2} + 28 x ) ( x + 3 ) - 1 \cdot ( x ^{4} + 7 x ^{3} + 14 x ^{2} )}{( x + 3 ) ^{2}}

Simplify

\frac{( 4 x ^{3} + 21 x ^{2} + 28 x ) ( x + 3 ) - 1 \cdot ( x ^{4} + 7 x ^{3} + 14 x ^{2} )}{( x + 3 ) ^{2}} : \frac{3 x ^{4} + 26 x ^{3} + 77 x ^{2} + 84 x}{( x + 3 ) ^{2}}

= \frac{3 x ^{4} + 26 x ^{3} + 77 x ^{2} + 84 x}{( x + 3 ) ^{2}}

\int 3 y^{2} d y

x \to 6 + lim (\frac{- 5 x}{x + 6})

\int (sin (2 x) cos (2 x)) d x

\frac{d}{d x} (e^{x^{3} y})

\frac{\partial}{\partial y} (\frac{x + y}{x - y})

What is the derivative of (x^4+7x^3+14x^2/(x+3)) ?
The derivative of (x^4+7x^3+14x^2/(x+3)) is (3x^4+26x^3+77x^2+84x)/((x+3)^2)
What is the first derivative of (x^4+7x^3+14x^2/(x+3)) ?
The first derivative of (x^4+7x^3+14x^2/(x+3)) is (3x^4+26x^3+77x^2+84x)/((x+3)^2)