What is the derivative of (3-2x^2) ?

The derivative of (3-2x^2) is -4(3-2x)

What is the first derivative of (3-2x^2) ?

The first derivative of (3-2x^2) is -4(3-2x)

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\frac{d}{d x} ((3 - 2 x)^{2})

- 4 (3 - 2 x)

Solution steps

\frac{d}{d x} ((3 - 2 x)^{2})

Apply the chain rule:

2 (3 - 2 x) \frac{d}{d x} (3 - 2 x)

= 2 (3 - 2 x) \frac{d}{d x} (3 - 2 x)

\frac{d}{d x} (3 - 2 x) = - 2

= 2 (3 - 2 x) (- 2)

Simplify

= - 4 (3 - 2 x)

f (x) = \frac{2 x}{x ^{2} + 1}, (- 1, - 1)

\frac{2 ( x + 1 )}{x ^{2} + 1}

r^{2} - 9 x^{2}

N - 0.0002 N^{2} = \frac{d N}{d t}

x \to \infty + lim (x^{10})

What is the derivative of (3-2x^2) ?
The derivative of (3-2x^2) is -4(3-2x)
What is the first derivative of (3-2x^2) ?
The first derivative of (3-2x^2) is -4(3-2x)