What is the tangent of f(x)=(2x)/(x^2+1),(-1,-1) ?

The tangent of f(x)=(2x)/(x^2+1),(-1,-1) is y=-1

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tangent of f(x)=(2x)/(x^2+1),(-1,-1)

tangent

y = - 1

Solution steps

Find the slope of

f (x) = \frac{2 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(- 1, - 1) : y = - 1

y = - 1

What is the tangent of f(x)=(2x)/(x^2+1),(-1,-1) ?
The tangent of f(x)=(2x)/(x^2+1),(-1,-1) is y=-1