What is (\partial)/(\partial x)(y^2cos(x)) ?

The answer to (\partial)/(\partial x)(y^2cos(x)) is -y^2sin(x)

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(\partial)/(\partial x)(y^2cos(x))

\frac{\partial}{\partial x} (y^{2} cos (x))

- y^{2} sin (x)

Solution steps

\frac{\partial}{\partial x} (y^{2} cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y^{2} (- sin (x))

Simplify

= - y^{2} sin (x)

\frac{\partial}{\partial x} (sin (9 x + yz))

\frac{d}{d x} (\frac{x ^{3} - 2 x + 4}{x ^{3}})

\int x (5 x - 3)^{2} d x

\int e^{3 x} + \frac{1}{x} d x

\frac{d}{d x} (x \frac{d y}{d x})

What is (\partial)/(\partial x)(y^2cos(x)) ?
The answer to (\partial)/(\partial x)(y^2cos(x)) is -y^2sin(x)