(\partial)/(\partial x)(sin(9x+yz))

解答

\frac{\partial}{\partial x} (sin (9 x + yz))

cos (9 x + yz) \cdot 9

求解步骤

\frac{\partial}{\partial x} (sin (9 x + yz))

将

y, z

视为常数

使用连锁律:

cos (9 x + yz) \frac{\partial}{\partial x} (9 x + yz)

= cos (9 x + yz) \frac{\partial}{\partial x} (9 x + yz)

\frac{\partial}{\partial x} (9 x + yz) = 9

= cos (9 x + yz) \cdot 9

\frac{d}{d x} (\frac{x ^{3} - 2 x + 4}{x ^{3}})

\int x (5 x - 3)^{2} d x

\int e^{3 x} + \frac{1}{x} d x

\frac{d}{d x} (x \frac{d y}{d x})

y^{^{'}} + 3 y = 2 e^{- 3 t}