What is the derivative of 4x+2x^2sin(1/x) ?

The derivative of 4x+2x^2sin(1/x) is 4+2(2xsin(1/x)-cos(1/x))

What is the first derivative of 4x+2x^2sin(1/x) ?

The first derivative of 4x+2x^2sin(1/x) is 4+2(2xsin(1/x)-cos(1/x))

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\frac{d}{d x} (4 x + 2 x^{2} sin (\frac{1}{x}))

4 + 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

Solution steps

\frac{d}{d x} (4 x + 2 x^{2} sin (\frac{1}{x}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (2 x^{2} sin (\frac{1}{x}))

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2 x^{2} sin (\frac{1}{x})) = 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

= 4 + 2 (2 x sin (\frac{1}{x}) - cos (\frac{1}{x}))

\int sin (x - n x) d x

\frac{d}{d x} ((5 x - 1 + 2)^{6})

\int_{- 2}^{3} x^{2} + 4 d x

\int \frac{e \frac{1}{x}}{x ^{2}} d x

y^{^{'}} + 2 x y = 0

What is the derivative of 4x+2x^2sin(1/x) ?
The derivative of 4x+2x^2sin(1/x) is 4+2(2xsin(1/x)-cos(1/x))
What is the first derivative of 4x+2x^2sin(1/x) ?
The first derivative of 4x+2x^2sin(1/x) is 4+2(2xsin(1/x)-cos(1/x))