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Popular >

y^'+2xy=0

Solution

y^{^{'}} + 2 x y = 0

Solution

y = e^{- x^{2} + c_{1}}

Solution steps

y^{'} (x) + 2 x y = 0

Solve separable ODE:

y = e^{- x^{2} + c_{1}}

y = e^{- x^{2} + c_{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=0 ?
The solution for y^'+2xy=0 is y=e^{-x^2+c_{1}}