What is the tangent of 5/(4-x),\at x=-3 ?

The tangent of 5/(4-x),\at x=-3 is y= 5/49 x+50/49

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tangent of 5/(4-x),\at x=-3

tangent of

\frac{5}{4 - x}, at x = - 3

y = \frac{5}{49} x + \frac{50}{49}

Solution steps

Find the tangent point:

(- 3, \frac{5}{7})

Find the slope of

y = \frac{5}{4 - x} : \frac{d y}{d x} = \frac{5}{( 4 - x ) ^{2}}

Compute the slope of

y = \frac{5}{4 - x}

x = - 3 : m = \frac{5}{49}

Find the line with slope m=

\frac{5}{49}

and passing through

(- 3, \frac{5}{7}) : y = \frac{5}{49} x + \frac{50}{49}

y = \frac{5}{49} x + \frac{50}{49}

\int \frac{1}{- x ^{2} + 10 x} d x

\int x^{7} \cdot sin (x^{4}) d x

f (x) = cos (x^{2})

n = 1 \sum \infty n (\frac{4}{3})^{n}

f (x) = 2 x - 3 x^{2}, at x = - 1

What is the tangent of 5/(4-x),\at x=-3 ?
The tangent of 5/(4-x),\at x=-3 is y= 5/49 x+50/49