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Popular >

sum from n=1 to infinity of n(4/3)^n

Solution

n = 1 \sum \infty n (\frac{4}{3})^{n}

Solution

diverges

Solution steps

n = 1 \sum \infty n (\frac{4}{3})^{n}

Apply Series Ratio Test:

diverges

= diverges

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Frequently Asked Questions (FAQ)

What is the sum from n=1 to infinity of n(4/3)^n ?
The sum from n=1 to infinity of n(4/3)^n is diverges