What is the solution for y^{'''}-9y^{''}+20y^'=0 ?

The solution for y^{'''}-9y^{''}+20y^'=0 is y=c_{1}+c_{2}e^{4t}+c_{3}e^{5t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{'''}-9y^{''}+20y^'=0

y^{^{'''}} - 9 y^{^{''}} + 20 y^{^{'}} = 0

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

Solution steps

y^{'''} (t) - 9 y^{''} (t) + 20 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

y = c_{1} + c_{2} e^{4 t} + c_{3} e^{5 t}

What is the solution for y^{'''}-9y^{''}+20y^'=0 ?
The solution for y^{'''}-9y^{''}+20y^'=0 is y=c_{1}+c_{2}e^{4t}+c_{3}e^{5t}